C question based on switch

Question

Why is the output of the code below "abc" ? Does the switch take the case before default always, if a variable is not specifed?

switch(printf("ab")){
case 1:printf("b");
break;
case 2: printf("c);
break;
default:printf("z");
}

Answer 1

Actually the 2 characters printed are 'a' and 'b'. Result of printf is 2 (number of characters output) and inside the switch a 'c' is also printed.

Answer 2

\0 is not printed.

Answer 3

because "a" contains two characters, 'a' and '\0', and printf returns the number of bytes printed, so it executes case 2.

Answer 4

Yes, but Bebida told it as a and \0, as I had previously missed a 'b' in the code😅

Answer 5

the output is automatically abc because of the above reason

Answer 6

printf("ab") is equal to 2
so that the value c is displayed

Answer 7

It is correct