Valid email tester,

Question

Okay so I made it like this,

l = ["@", "."]

c = 0

while True:

inp = input(" Email: ")

for i in l:
c = c + 1
if inp != c or inp != c:
print(" Invalid")
else:
inp == c and inp == c
print("Your E-mail was " + inp + " and it is a valid email.")
break

How come it won't find the @ and the .?

Answer 1

Ok, so your for loop looks, in the first iteration, for an ‘@‘, but it only looks in one place (i.e. in position ‘c’). Maybe try something like this:

found_at = False
found_dot = False

for c in range(len(inp)):
if inp[c] == “@“:
found_at = True
if inp[c] == “.”:
found_dot = True

if found_at and found_dot:
print(“email valid”)
else:
print(“email invalid”)

I’m in a hurry so this is highly rudimentary but hopefully it should explain the point that you have to check every character of inp against @ and . not just one per iteration.

Also, currently what I’ve given you doesn’t check that the @ comes before the .

Hooe that’s at least some help.

Answer 2

I gave it a shot with just one, and it's still not looking for the library?

for i in l:
c = c + 1
if inp [c] != i:
print(" Invalid")
else:
inp [c] == i
print("Your E-mail was " + inp + " and it is a valid email.")
break

How would I write it to look for the @ and . in my input?

Ex.

Enter an email address: [e-mail]

Great, [e-mail] is a valid email address!

Enter an email address: notmyemail

I'm sorry, notmyemail is not a valid email address

Answer 3

thanks man im excited!

Answer 4

There are a few issues here:

You’re comparing the whole input (inp) to an integer (c), rather than individual characters of inp. You may need

if inp[c] != i:

or something like that since I’m not completely sure how you’re designing your algorithm.

Definitely, though,

if inp != c or inp != c:

is superfluous as it’s the same test being conducted twice, and

inp == c and inp == c

is meaningless. Aside from it again being the same thing twice, inp == c is a comparison, but it’s not used in an if statement.

To answer your question about it not finding @ or . though, you have

for i in l:

which is correct, but you’ve not used i in the code in your loop.

Answer 5

Thank you Russ :D

Answer 6

No worries. If you need any further help, I’ll see what I can do later on.

Answer 7

f_a = False
f_d = False

while not f_a or f_d:
inp = input(" Email: ")

for char in inp:
if char == "@":
f_a = True
if char in inp:
f_d = True

if f_a and f_d:
print(" Your E-Mail " + inp + " was valid. ")
else:
print(" Try again. ")

I got it down :D thanks Russ,

now I know you can use True and False for finding memory logs in Python. How cool is that.

Answer 8

Good stuff. Have you tested it?

Answer 9

yes and works perfectly now to get to more addins

Answer 10

i redid the whole code with my own, it wont work if there is only a @ in the input

Email: i@icom

Output: Try again

Email: @.

Output: Valid

Answer 11

Ah ok. The code you posted above returns valid for i@icom.

Good work!

Answer 12

Are you sure? 😉

Did you try inputting something like me@myaddress?

Not trying to nitpick, but I always like to know if someone finds a bug in my codes.