Python question

Question

The question is as follows:

For i in range(1,5):
print(i%3)

It says the output is 1201, and I am completely clueless as to why? Could anyone help out?

Answer 1

The "for in" loop goes over the variable i from 1 to before 5, so...

First: i % 3 would be 1 % 3, 3 goes into 1, 0 times and then the remainder is "1".
Second: i % 3 would be 2 % 3, 3 goes into 2, 0 times and then the remainder is "2".
Third: i % 3 would be 3 % 3, 3 goes into 3, 1 time and there is no remainder so that results in "0".
Fourth: i % 3 would be 4 % 3, 3 goes into 4, 1 time and there is a reminder of "1".

Then that is the end of the loop so looking at all 4 outputs that would be "1201"

EDIT:
No Problem 🙂

Answer 2

The output is
1
2
0
1
which is correct.

The 'for' loop (note the small 'f'!) iterates through range(1,5), i.e. it processes the integers 1, 2, 3 and 4.

For each of those numbers, i%3 is printed on a separate line.

% is the modulo operator, which can be thought of as the remainder after a division.

1%3 is calculated like this: 3 goes into 1 zero times with 1 left over, so 1%3 is 1

2%3 : 3 goes into 2 zero times with 2 left over, so 2%3 is 2

3%3 : 3 goes into 3 1 time with 0 left over, so 3%3 is 0

4%3 : 3 goes into 4 1 time with 1 left over, so 4%3 is 1

i.e. the answer is
1
2
0
1

Hope this helps :)

Answer 3

Thanks David and LynTon!