Why can't it print the value from the address directly?

Question

If:

int x = 10; // declares variable x
int* p = &x; // declares variable p and assigns the address of x

cout << p << endl; // prints: 0x23fe44

cout << *0x23fe44 << endl;
Why does the line above not work?

Isn't it the same as the line below?
cout << *p << endl;

Answer 1

Thanks! Undertand pointer clearer now.

Answer 2

pointer is a data type that can store an address.

* is a function of that datatype that allows access of the data at the address.

The address itself hasn't got that 'access me' button.