Hexadecimal addressing of integers

Question

just wondering why in the playground the hexadecimal address is Xo29fee8 for an integer if an integer is 2 bytes why do you have 24 bits to address 16 bits?

Answer 1

I guess X029fee8 is only the *address* of that integer. Roughly speaking, the place in the RAM where the integer is stored, rather than the integer itself.
[EDIT] I mean, every pointer to any data type (integer, char, string, double, etc.) will have 24 bits.