What to do when it is saying outside the loop in python

Answer 1

Anshuman The while loop is never executed since the condition is false. This might make more sense:

n = 1
while n <= 5:
print(n)
n = n + 1
if n == 4:
print("Four")
break

The error you got might be due to the Indentation of "break" since break statement should be inside of any loop, not outside. Here's *your* code with proper indentation:

n = 1
while n >= 5: # Always false
print(i) # 'i' is not defined
n = n + 1
if n <= 9:
print("Four")
break

Edit: Glad I could help.

Answer 2

You are correct Anna. I was just about to point that out and was writting it when you jumped the gun. That was exactly the concept I mentioned in my answer. ⚒️Raj Chhatrala🛡️ please fix your answer or Anshuman might live with false concepts.

Answer 3

Can you show the code you're getting this error in?
Maybe I or someone else can help you if we have code.

Answer 4

As kainatic said your loop will never run because of it's termination condition.

And the error is due to indentation of break statement.
So proper indentation will fix it

edit : check out answer by Anna

Answer 5

⚒️Raj Chhatrala🛡️ You can use break outside of an if/else statement, but not outside of a loop 👆

Answer 6

n = 1
while n >= 8:
print(n)
n = n + 1
if n >= 5:
print("Four")
break

Answer 7

Thank you so much kainatic i tried your code and it worked

Answer 8

And thank you so much to Raj Chhatrala that you made my concept so much clear than before