This code outputs '4' and I wanna know why [explain line by line if you can ; please ] thanks in advance .

Question

int x=1;
switch (x) {
case1 : x++;
case2 : x++;
default : x++;
}

cout<< x ;

Answer 1

There's no "break" keyword. So when the case matches (case 1:), it just proceeds to execute the code under. You will end up with 3 increments, which will give you 4 as a result.

Answer 2

And for example if x=2, it will skip the first one, because it is lower than x.

Answer 3

You r missing break; statement.
It just increments 1 in each increment statements and outputs 4 .
Technically it is not a switch case program....

Answer 4

use break statement and compile it again