Hi plzz! i need some help i dont feel well! anyone tell me how to s.o.p in a nonincreasing way an array please Here's the src👇

Question

import java.util.Scanner;
public class test
{
public static void main(String[] red)
{
int tab[]={1,2,3,4};
int tmp;
for(int i=0;i<4;i++)
{
if(tab[i]<tab[i+1])
{
tmp=tab[i];
tab[i]=tab[i+1];
tab[i+1]=tmp;
}
}

for(int i=0;i<4;i++)
{
System.out.println(tab[i]);
}
}

}

Answer 1

Airree
Sorry but you are wrong 😉
you can place any name in place of args

In that code the problem was arise in line no 10 chek it out

Answer 2

I think you want in that array elements are placed in decrising order.

Answer 3

you have index 0 to 3 but you address 3 and 3+1 and it is out of index, here:
if(tab[i]<tab[i+1])

do this
for(int i=0; i<3; i++) {

To sort the array in this way, 3 is not enough cycles to complete this array

Answer 4

Yh! But u can change the args if u want it is not a problem.

Answer 5

The problem is with this code, that it doesn't run the main method because you didn't write String[] args. Otherwise, I see no problems with your code

Answer 6

Yes, but java takes only methods that are public static void main(String[] args) as an entry point; otherwise it is just a normal method

Answer 7

No i think so to java the keyword is main

Answer 8

Did u try to run it please?

Answer 9

To follow conventions u can't change but if u do it is not a problem

Answer 10

I know its in line 10 but im stucked