How to make this code run my way?

Question

There are two strings a and b that mean smart and dumb

Code:

a = "smart"

b = "dumb"

print("Lions" + " are " + input())

When I enter a or b in the pop box it doesn't show smart or dumb.
For ex:
It only shows "Lions are a" or "Lions are b"

Answer 1

It will take your input as a string and have no idea that if you enter "a", you're referring to the variable a. So it'll just print your input as a string.

Theoretically, you could use the eval() function to evaluate your input:

print("Lions are " + eval(input()))

However, this is very dangerous and shouldn't be done.

The safest way is to take input as a string and check what was entered:

user_input = input()

if user_input == 'a':
(...)
elif user_input == 'b' (...)

You could also use a dictionary:

d = {
'a': 'smart',
'b': 'dumb',
}

print("Lions are " + d.get(input(), 'meh...'))

Answer 2

hi Seb, that's really smart code. 👍

Answer 3

Using eval works, some developers don't recommend using eval within input statements, but here is another method:
#Defining function:
def a_or_b(a, b, put):
if put == "a":
return a
elif put == "b":
return b
else:
return "not smart, but not dumb"

print("Lions" + " are " + a_or_b(a, b, input()))
#if input == "a": Lions are smart
#elif input == "b": Lions are dumb
#else: Lions are not smart, but not dumb

Answer 4

Lothar I know Python good enough for that to be nothing. But thanks.

Answer 5

What is the easiest programing language to start with ?

Answer 6

Of the three ,which is easier to learn first;
Java
Python
C

Answer 7

sande morris Python is typically the beginner friendliest programming language of those 3.