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Isn't the character array variable name a pointer to array in C ?
Why there is an error while running this code : "function returns address of local variable". Wasn't ch (See the code) a pointer to the character array, and hence we are returning the starting address of the array. Can anyone help me out : CODE : #include<stdio.h> char * function() { char ch[10] = "Thanks"; return ch ; } int main() { char * point = function(); printf("%s",point); return 0 ; }
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~ swim ~
If the array in the function gets erased after the function returns to the main(). Then even if i store the address of the first element (ch[0]) in a character pointer ie. "char * ptr" and return ptr, it should also point to garbage but the program runs fine.
Any explanations ?