Why 5th position printed as zero I expected it as 16

Question

#include<stdio.h>
int main() {
char c=48;
int i, mask=01;
for(i=1; i<=5; i++)
{ printf("%c", c|mask);
mask = mask<<1;
}
return 0;
}

Answer 1

Because your type specifier is %c, which means a character, the value of c will stay 48 in the fifth iteration, 48 is ASCII is 0, plus there's no character "16" in ASCII. If you want to do that, I suggest you to use an integer instead