How to count the frequency of a letter in a word in python??

Answer 1

word = 'mississippi'
for letter in set(word):
print(letter, '=', word.count(letter))

Answer 2

s=input()
for i in range(len(s)):
if s[i] not in s[:i]:
print(s[i]+"="+s.count(s[i]))

Answer 3

word = 'googlegooglehalohalo'
print(",".join(set(list(map((lambda x:x+"="+str(word.count(x))),word)))))

Answer 4

Mateusz R

It won't work.

Try replacing variable 'str' to 'txt' or else.

It will work.

Answer 5

def count(word):
result = dict()
for line in word:
local = word.count(line)
result[line] = local

return result

print(count("google"))

Answer 6

Why r u going for some tough solutions?
Wanna Make it easy see here!!1

Letter Frequency Problem --

text=input()
letter=input()

count=0
for i in range(0,len(text)):
if letter==text[i]:

count+=1

fre=int((count/len(text))*100)
print(fre)

Answer 7

I extended my code with the functionality you want. Take a look Siddhi.

Answer 8

str = "SoloLearn"

freq = {}

for i in str:
if i in freq:
freq[i] += 1
else:
freq[i] = 1

print ("Frequency :\n "
+ str(freq))

Answer 9

This is one of possible solutions:
https://code.sololearn.com/cz2fEt6X87D9/#py

Answer 10

'mississippi'.count('i')

Answer 11

I want the output like
Input string :google
Output:
g =2
o=2
l=1
e=1

Answer 12

In c I use the array method to find the frequency...
But in python array is not native you can use the numpy library for that ... Hope it will help

Answer 13

Here my code.
I tried to do in a beginner way ( very straightforward )

a=input()
b=input()
c=len(a)
cont = a.count(b)
volte = int((cont/c)*100)
print(volte)