Help with Regular Expressions

Question

I want to find this in strings:

%RED%
%BLUE%
%JEKFJ%
etc.

I tryed with:
/%+[a-zA-Z]+%/
/(%+[a-zA-Z]+%)/
/((%{1})+[a-zA-Z]+(%{1}))/

But it, or don't work, or select strings with more than one "%", for example "%%RED%"

Answer 1

InvBoy [ :: FEDE :: ] you can see it in the code. If you need to match a string with exact start and end use the tokens for start =>"^" and end =>"quot;. Hope it helps you 😉.
https://code.sololearn.com/WS4mwwYKoy0x/?ref=app

Answer 2

Try (%[a-zA-z]+%), worked fine for me :)

Answer 3

/%[A-Z]+%/ will match all of these.

If you want to exclude items with two %% for example, your need to tell the regex engine what to expect before the %. If you just don't want to allow %% at the beginning, then use this:
/(?:[^%])%[A-Z]+%/

Answer 4

Don't listen to Cbr✔[ Most active ]
That answer is wrong despite the upvotes!?
Would only match 1 character between the % -- total nonsense.

Answer 5

As you need to find specific words and characters that are known, I think you can use the following regex: \%(RED|BLUE|JEKFG)\%
Here the code:https://code.sololearn.com/c6JlVeLwr05h/?ref=app