Diamond pattern

Question

I have a code of mine which I believe can be simplified.
Please help me
https://code.sololearn.com/cQZosG9dtP1k/?ref=app

Answer 1

Thank you .😊😊

Answer 2

I found a few ways to simplify and make the code more understandable to people.

Here are a few improvements explained:
- Replaced "\n" with endl. Sending "\n" out to break a line works but endl is generally what c++ uses for the job. endl will also get replaced with \r\n, \r in operating systems that use different line break character combinations.

- Output "* " together instead of "*" << " ". "* " is shorter and a little easier to read.

- Created printLine function. Your code had 2 sections duplicating the effort of printing a line with appropriate spaces followed by the asterisk pattern. Instead of duplicating the code, the new printLine function can be called twice.

- Renamed a couple variables. diamondSize seemed more understandable than n.

- Added more comments. A few steps and the function looked like it would be more easily understood by a few comments.

- Added more spaces and blank lines. This might be a tiny improvement in readability but it could just be my personal preference too.

Here is my tweaked version:
// Creates a diamond pattern of *
//where n is the maximum number of dots.
//Example n=4
//Pattern is
// *
// * *
// * * *
//* * * *
// * * *
// * *
// *

#include <iostream>
using namespace std;

// Prints a line of spaces and asteriskCount asterisks
// Assumption: asteriskCount < 27.
void printLine(int asteriskCount) {
int i;

for (i=27 - asteriskCount;i>=0;i--)
cout << " ";

for (i = 0; i < asteriskCount; i++)
cout << "* ";

cout << endl;
}

int main()
{
int i, diamondSize;
cout << "Enter the maximum number of dots ";
cin >> diamondSize;
cout << endl;

// Print top triangle.
for (i=0; i<=diamondSize; i++)
{
printLine(i);
}

// Print bottom triangle.
for (i-=2; i>0; i--)
{
printLine(i);
}
return 0;
}

Answer 3

#include <iostream>
using namespace std;
int main()
{
int space=10,n,i;
cin>>n;
for ( i=0;i<n;i++)
{
for (int j=0;j<=space;j++) cout<<" ";
for (int k=0;k<i;k++) cout<<"*";
cout<<endl;
space--;}

for (i=n;i>=0;i--)
{
for (int j=0;j<=space;j++) cout<<" ";
for (int k=0;k<i;k++) cout<<"*";
cout<<endl;
space++;
}

}

Answer 4

it's super cute!!

Answer 5

#In python, Single line of code using Comprehension

n=5
print('\n'.join([('* '*i).center(2*n) for i in range(1,n+1)] + [('* '*i).center(2*n) for i in range(n-1,0,-1)]))

Answer 6

https://code.sololearn.com/c8OeV7di4VTn/?ref=app