How to take the cube root of a number in python using exponentiation ?

Question

I want to make a calculator code which has the option of cube root. I know how to take the square root of a number. but what about cube roots ? any help would be appreciated.
thank you!

Answer 1

Just use the inverse of the power raised.

N**(1.0/3.0)

note, this only works for positive values of N.

Answer 2

You can use
pow(x, y)

x - the number whose root you want to find
y - the degree to which to raise the number
If y = 1/3 then you get the cubic root

pow(27,1/3)

Answer 3

Thanks a lot Михаил Горчанюк and Robert Atkins

Answer 4

Thanks a lot Paolo De Nictolis and Ankit Raghuvanshi

Answer 5

Ankit Raghuvanshi ☺

Answer 6

Newton-Raphson only needs 8 iterations for sqrt(27) (even when you start with a very poor initial estimate at 1):

c = 0
n = 27
y = 1

while abs(y**3 - n) > 0.00001:
y = y - (y**3-n)/(3*y**2)
c+= 1
print("iterations: ", c)
print(round(y))

Answer 7

thank you so much Thoq!

Answer 8

I will do that Thoq! and thanks a lot for recommending

Answer 9

Thanks Utkarsh Pratap Maurya

Answer 10

thank you so much Egbeola Samuel ☺

Answer 11

Thoq!, i just wanted to know the different methods of getting cube roots.

check out this code and please tell me if i can add anything else
https://code.sololearn.com/cQ2Wc082SeBM/?ref=app

Answer 12

sujay simha I know that this is not really what you were looking for. But I still found it might be interesting to show how a (simple) implementation for finding a root might look like.

Answer 13

sujay simha When taking a look at my calculator, I can see a lot of stuff like sine, cosine, log, tan, mean... which you could also implement.

Answer 14

like this
4***3

Answer 15

pow(a,b)
b=1/3 while
a= The number you want to find the cube root of

Answer 16

You are always welcome with more problems

Answer 17

Import math as m
a, b=int(input("enter a number ")), int(input("enter power"))
s=m.pow(a, b)
print(s)

Answer 18

pow(num, 1/3)

Answer 19

thnx

Answer 20

This has solved a lot of my problems