What is the output of this code? And How?

Question

def f(r):
j = range(r)
e = eval("*".join([str(i+2) for i in j]))
return e
print(f(3))

Answer 1

so if I am getting this corrextly
j = 0,1,2 (because range is 3)
and it does each of those + 2
so 2,3,4
and because the string is joined with * (which after eval is just a multiplier)
it becomes 2*3*4 = 24 :)

Answer 2

I guess so thanks guys. That's right Brave Tea ~ swim ~

Answer 3

When I run this code, it provide the results 24. But I don't understand why? I need to understand clearly and I need the clue. So that I asked.. Thanks

Answer 4

interesting eval() parses a string as an expression, so everything that is a string inside the eval() will become an expression. so “*” is actually just a multiplier here :)

https://www.programiz.com/JUMP_LINK__&&__python__&&__JUMP_LINK-programming/methods/built-in/eval

Answer 5

Yes I am already in programiz.com and learning eval(), how its works. But If you guys do have any ideas about this method you can share.

Answer 6

Brave Tea By the way Thanks for sharing.

Answer 7

welcome :) I liked your post as well. made me learn something as well :)

Answer 8

24 :) but no clue why. :) will look into it later but will probably be answered by then :)