Fill in the blanks to define a function ''myFunc'', which throws an exception if its parameter is less than 0. void myFunc(int a

Question

ho do work out this

Answer 1

Ans:
void myFunc(int arg)
throws IllegalArgumentException
{ if(arg <0)
throw newIllegalArgumentException();
}

Answer 2

public void do(int x)
throws IOException {
if(x<0)
{
throw new IOException();
}
}

Answer 3

throws
if
0
new

Answer 4

if (a < 0) throw new IllegalArgumentExcpetion("Parameter cannot be negative");

Answer 5

public viid(int x);
throws IOException{
if(x<0)
{

throw new IOException();
}
}

Answer 6

public void do(int x){
try IOException{
if(x<0){
throws new IOException
}
}
}

Answer 7

Fill in the blanks to handle all possible exceptions.

Answer 8

Fill in the blanks to declare a method that takes one argument of type int.

public int myFunc(

x)

return x*10;

I need help

Answer 9

Drag and drop from the options below to create a method that throws an IOException if the parameter is negative.

Answer :-
public void do(int x)
throws IOException {
if(x<0)
{
throw new IOException();
}
}

Answer 10

public void myFunct(int arg)
throws IllegalArgumentException
{
if(arg<0)
{
throw new IllegalArgumentException();
}
}

Answer 11

answers in order:

throws
IOException
throw
new

Answer 12

throws
if
0
new

Answer 13

throws
IOException
throw
new

Answer 14

throws
if
0
new

Answer 15

Drag and drop from the options below to create a method that throws an IOException if the parameter is negative

ANS:public void do(int x)
throws IOException {
if(x<0)
{
throw new IOException();
}
}

Answer 16

public void do(int x)
throws IOException {
if(x<0)
{
throw new IOException();
}
}