1 Antwort
+ 5
For the studying purposes represent your number as binary:
5 -> 00000101
1. Now shift it right to 2 positions (x>>2) as it is written in first half of your example:
00000101 >>2 -> 00000001 (we 'lost' rightmost '1').
So we've got 00000001 (1).
2. Now shift the result left to 5 positions (as in your example's second half (<<x), assuming that x equals 5:
00000001 << 5 -> 00100000
So we have 00100000 nowm which is 32 in decimal.