How to covert letter 'A' to letter 'B' using ASCII code?

Question

Also mention if there is any other way to solve the problem....

Answer 1

char type internally stores a number (8bit integral value) and you can manipulate it as you would any integral value.

That is, you can use ++ or -- operator to increment or decrement the value, and hence also the character it represents.

char c {'A'};
std::cout << c++ << std::endl; //post increment, here <c> still holds 'A'
std::cout << c << std::endl; // here <c> has incremented to become 'B'

Hth, cmiiw

Answer 2

https://code.sololearn.com/cOVH3IjA6uss/?ref=app

Answer 3

Pseudocode:

ASCII("B") = ASCII("A") + 1

They follow each other in the alphabet

Answer 4

https://code.sololearn.com/cS8XiA8J3QrU/?ref=app