TA =√s(s-a) (s-b) (s-c) were s =a+b+c/2

Question

i want a program

Answer 1

MATHHH NOOOO RUNNN!!!!

Answer 2

really s =a+b+c/2 and not s =(a+b+c)/2 ?

double a, b, c;
//Do sth with a, b and c
double s = (a+b+c)/2;
double TA = sqrt(s*(s-a)*(s-b)*(s-c));

pretty straightforward

Answer 3

You can get the complete Code for this Program on my Profile.

Answer 4

#include <iostream>
#include <cmath>
using namespace std;

int main() {
int a=5;
int b=4;
int c=6;

float s= float((a+b+c))/2;
float TA=sqrt(s*(s-a)*(s-b)*(s-c));
cout <<TA;
return 0;
}