Python - Logical operators evaluation order

Question

Why these results? Especially, why is c 1?

a = 0 and 1 or 0
b = 0 and 0 or 1
c = 1 or 0 and 0
d = 0 or 1 and 0
print(a,b,c,d,sep='')

Answer 1

Boolean operators from lowest precedence to highest precedence: OR, AND, NOT.
https://docs.python.org/3/reference/expressions.html#operator-precedence

Therefore, the expressions are evaluated as:

a = (0 and 1) or 0
# 0 or 0 == 0.

b = (0 and 0) or 1
# 0 or 1 == 1.

c = 1 or (0 and 0)
# 1 or 0 == 1.

d = 0 or (1 and 0)
# 0 and 0 == 0.

Answer 2

Always first AND, then OR. Understood.

Answer 3

Yes, but WHY?

Answer 4

And.... What's the rule? ☺️

Answer 5

a = 0 and 1 or 0
b = 0 and 0 or 1
c = 1 or 0 and 0
d = 0 or 1 and 0
print(a,b,c,d,sep='')
#0110

Answer 6

they are probably executed in this order:

a = 0 and (1 or 0)
b = (0 and 0) or 1
c = 1 or (0 and 0)
d = (0 or 1) and 0
print(a,b,c,d,sep='')

it really is weird, but by placing brackets you can make it the order is right...

Answer 7

I'm giving up