when I call re.findall(x, "s)s)s") for x = r”)” it returns an error. Is there a way to make it not do that?

Question

“””
I know the parentheses are unbalanced but it seems like it should just print a list of every “)” in the string.
“””

import re

patt1 = r"s"

patt2 = r")"

a = int(input())

if a % 2 == 0:
x = patt1
else:
x = patt2
print(re.findall(x, "s)s)s"))
https://code.sololearn.com/cXg04479cP9u/?ref=app

Answer 1

The parenthesis '(' and ')' are special characters in regex. To match them use '\(' or '\)', or enclose them inside a character class: '[(]', '[)]'.
https://docs.python.org/3.7/library/re.html#index-14

patt2 = r"\)"
print(re.findall(x, r"s\)s\)s"))