Why does this give no output (in new to c and c++)

Question

Code : https://code.sololearn.com/ct06gCh9y26J/?ref=app

Answer 1

printf("%d. %s",i,i);

the '%d' expect an int and you give it at parameter, but '%s' expect a string and you give it the same integer: either the mistake is in this second parameter type, either it's in the format parameter in the 'placeholder' ( pre-formatted ) string... As you don't have any string variable declaration in your code, try to change by:

printf("%d. %d",i,i);

Answer 2

Yes, it should work too ;)

Answer 3

Yep :P

You'll try to convert an integer between 0 and 128 to a single char: it couldn't work ^^
With %d ant the int it work... if you like to convert the second int to a char, try that:

printf("%d. %c",i,(char)(i+65));

You must change %s in %c, and add some count to your int, so the range isn't arround 0 ( first ascii char are non printable commands )...

Answer 4

Changing %s to %c did it. It works now thanks...

Answer 5

How about if I type cast the second integer to char.. It should print the char right?

Answer 6

Did it.. Still no output... I'm not even sure if my program is faulty or just Sololearn is messing something up... It just says "no output"