Python arrays - Quite complicated an assignment....

Question

It seems to me this code:

arr = [4,3,1,2]
arr[0], arr[arr[0]-1] = arr[arr[0]-1], arr[0]
print(arr)

functions as per these steps:

1) arr[arr[0]-1] = arr[3] = 2 and arr[0] = 4 are stored "on the right"
2) arr[arr[0]-1] = arr[3] = 2 is assigned to arr[0]
3) now, arr[0] is changed to 2, so arr[arr[0]-1] = arr[1], and arr[1] is assigned value "4" previously stored "on the right".

Is it so?

Answer 1

Nikita, please stop spamming in the Q&A. if you keep it up you will be deactivated.

Answer 2

https://docs.python.org/3/reference/simple_stmts.html

Quoting 7.2. Assignment statements

"An assignment statement evaluates the expression list (remember that this can be a single expression or a comma-separated list, the latter yielding a tuple) and assigns the single resulting object to each of the target lists, from left to right."

So yeah, your description of the process is correct.

Answer 3

LONGTIE👔 lol. To late, whatever she did. You're right. She's blocked