Python claculator

Question

while (1):
a=int (input ("number1"))
b=int (input ("num2"))
c=input ("enter operator")
if a=="add":
e=a+b

here the while loop continues for ever....It takes only the input infinite times and doesnot do the calculation.....where am I going wrong

Answer 1

equation=input()
answer=eval(equation)
print(answer)
#there, a fully functional calculator

Answer 2

you two need hugs

Answer 3

it work now? you need to print the answer too

Answer 4

the if is outside the loop?

Answer 5

do Ahri Foxes answer..it is much cleaner and will work no problems

Answer 6

Hey! Your code don't work simply because you don't perform the good comparison :P

Look at the condtion of your 'if' statement: a=='add' but you need to c=='add', anyway else the condition is always false ^^

Answer 7

while(1)... 1 is equal to true. while is always true.. operator is c not a

Answer 8

i told you... 1. while(1) will always be true.. therefore will never exit.. 2. change if a=="add" to if c=="add"

Answer 9

If I write this code ....just it keeps asking for the inputs and doesnot do the calculation.... what is wrong with my code

Answer 10

I understood what u said Jay ....but my question is why does while loop not perform the calculation....It keeps asking for the variables only.....I have written if also in a indented way right...I want to do a infinite loop only!!so it wrote 1!!!!

Answer 11

I did change that add..!!!!

Answer 12

I wrote print also.....my question is.....like why does the while infinite loop apply only to getting of variables .....and not perform calculation.....when I remove while loop the calculator works fine

Answer 13

Is it outside????how can i include if also within while loop

Answer 14

Someone explain please