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Could anybody explain why j = - 2 in this code? (Java)

public class Program { public static void main(String[] args) { int i = 0, j = 0, k = 0; while(i < 2) { j = i++; System.out.println("step 1 i = " + i); System.out.println("step 1 j = " + j); while(j-- >= 0) k = k + ((j % 2 == 0) ? -1 : 1); System.out.println("step 2 j = " + j); System.out.println("step 2 k = " + k); } System.out.println("final i = " + i); System.out.println("final j = " + j); System.out.println("final k = " + k); } } Output step 1 i = 1 step 1 j = 0 step 2 j = - 2 step 2 k = 1 step 1 i = 2 step 1 j = 1 step 2 j = - 2 step 2 k = 1 final i = 2 final j = - 2 final k = 1

5th Oct 2019, 8:11 PM
Federico Riva
1 Antwort
+ 4
That's because of postfix decrement. Let's say after some iterations j = 0 the condition will be checked 0 >= 0, (True) j--; ---> j = -1 As condition is true, compiler will get inside the loop and condition will be checked again 1 >= 0, (False) j--; ---> j = -2 Now condition is false, loop will be terminated. And final value of j is -2.
5th Oct 2019, 8:56 PM
blACk sh4d0w
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