I want to execute this again mean after the one task the program ask do u want more calculation how can I do In this program

Question

#include <stdio.h>

int main()
{
int a,b;
char operand;
printf("Please choose the operand (+,-,*,/):");
scanf("%c",&operand);
printf("Enter the value of A and B");
scanf("%d %d",&a,&b);

switch(operand)
{
case '+':
printf("%d+%d=%d",a,b,a+b);
break;
case'-':
printf("%d-%d=%d",a,b,a-b);
break;
case'*':
printf("%d*%d=%d",a,b,a*b);
break;
case'/':
printf("%d/%d=%d",a,b,a/b);
break;
default:
printf("Error");
}
return 0;
}

Answer 1

just put main() before return 0 and you gat what you want, or use a loop which is a better option

Answer 2

Why u take 1 in the while loop?

Answer 3

You know in C/C++ any non zero integral value is considered a boolean true, passing in 1 is actually telling it to repeat forever, but we trap the loop with the confirmation of <again> at the bottom, the loop is broken if input for <again> neither equal to 'Y' nor 'y'.

Answer 4

You can also choose to use `do...while` loop, I think it makes more sense somehow. Because `do...while` loop runs at least once, before the loop condition is evaluated.

Answer 5

Hey asterisk I don't get the point?

Answer 6

Here's a picture of how you can do it with a loop. Hope this clears your doubt.

int main()
{
int a, b;
char operand, again; // add <again>

while (1)
{
// code to read operation here (+ - * / etc)
// code to read 2 numbers here
// code to calculate here (switch)
// ask whether to repeat again
printf("\nDo you want to calculate again? ");
scanf(" %c", &again);
if (again != 'Y' && again != 'y')
break;
}
return 0;
}