Why is this happening?

Question

This works (but the code below this one doesn't):

>>>x = list("1234")
>>>x
>>>['1', '2', '3', '4']
>>>x.append("5")
>>>x
>>>['1', '2', '3', '4', '5']

But if I directly do:

>>>x=list("1234").append("5")

Then this happens:

>>>type(x)
<class 'NoneType'>

Why?

Workaround of this problem:

>>>x=list("1234")+["5"]
>>>x
>>>['1', '2', '3', '4', '5']

How do they all differ and why?

Answer 1

The append() method modifies the existing. It doesn't return a new list. In fact, it returns None.

x = list("1234").append("5")
print(x) # None

https://stackoverflow.com/questions/3840784/

Answer 2

Its something like this:
if you do x("1234").append("5") its like youre creating the list while also appending 5, which might cause an error. First creating the list helps.

Answer 3

Dragon_King1111 I see, maybe that's the reason!!

Thanks 😊!
Happy Coding?

Answer 4

Diego Thanks man 👍! This one was the proper answer I was looking for!!

Happy Coding 😊!!