Why wont this work?

Question

This pequeno piece of code wont run coz I made "too many arguments to function 'int printSomething2()'". where did I go wrong?

#include <iostream>
using namespace std;

void printSomething();
int printSomething2();

int main(){

printSomething();

cout << printSomething2(9.95);
return 0;
}

void printSomething(){
cout << "Print this statement to the screen!\n";
}

int printSomething2(float a){
a + 13;
}
https://code.sololearn.com/c92x8c7UxiLm/?ref=app

Answer 1

In the prototype of printSomething2(), you declare it without a parameter. The function also doesn't return a value which may results undefined behavior.

Answer 2

CarrieForie thanks, I never paid attention to declaration of the prototype...