Output of the code ?and how?

Question

public class Program
{
public static void main(String[] args){
String s="a";
String v="x";
String t=s+v;
String z="ax";
if (t==z){
System.out.println (1);
}
else
System.out.println(0);

}
}

Answer 1

Thats i know Ipang what is the output of this code and why?

Answer 2

The output must be 0 because the assignment of the string "t" occur at the run-time and it is not considered as constant from the string pool.

Edit: make both your "s" and "v" variable as final and you will get "1" as answer. Since the final keyword makes them a constant.

Answer 3

Please edit your question and add Java in question tags.

Use `equals` method from string class if you want to compare string content.

if(t.equals(z))