28th Nov 2019, 9:11 AM
Jagbir singh
Jagbir singh - avatar
11 Antworten
+ 2
Apollo Don't practice these questions because the answer cannot be predicted correctly since the evaluation is compiler dependent is all that I'm trying to say. Press @ symbol and it will show you the names.
29th Nov 2019, 5:01 PM
Avinesh
Avinesh - avatar
+ 2
~ swim ~ thank you👍
28th Nov 2019, 12:40 PM
Avinesh
Avinesh - avatar
+ 1
But according to precedence postfix has higher priority so y is printed perfectly. Isn't it? I might be wrong or may be I am wrong. Quite confusing.
28th Nov 2019, 12:29 PM
Avinesh
Avinesh - avatar
+ 1
Apollo and Thé Ka|yan M!shrā Kindly read the answer provided by ~ swim ~ before you make any assumptions and get to a solution.
29th Nov 2019, 4:53 PM
Avinesh
Avinesh - avatar
+ 1
Avinesh , thanx
29th Nov 2019, 5:02 PM
Apollo
0
~ swim ~ So "y" is printed perfectly because "x--" means that it is not modified but only accessed and is only modified during "--x". Did I get it right?
28th Nov 2019, 11:48 AM
Avinesh
Avinesh - avatar
0
Actually, the x-- changes the value of x, but the program doesn't detect it until --x. Z, by the way, is ++b + --b Since b=5, ++5 is 6, and --6, our new b, is 5, 5+6 equals: 11
29th Nov 2019, 4:12 PM
Apollo
0
In the Z first increasing ++ b mean z=6 NOT increasing b Then by the add sign (+) and decrment -- that is --in the b so 5 become->4 Hence Z=6+4=10
29th Nov 2019, 4:48 PM
Thé Ka|yan M!shrā
Thé Ka|yan M!shrā - avatar
0
I was still close, right🙏
29th Nov 2019, 4:50 PM
Apollo
0
Avinesh, It's just practice for the challenges. I hope you understand that working hard in guessing an answer based on the code is fun.
29th Nov 2019, 4:58 PM
Apollo
0
By the way, how do you refer to people
29th Nov 2019, 4:59 PM
Apollo