Basic def and if python question

Question

I have written some pretty basic code here just trying to get it to tell me if x squared + 4 is less than 20 for a given x.

**************************
1 def f(x):
2 print((x**2) + 4)
3
4 x = 2
5
6 if f(x) < 20
7 print("true")
**************************

It keeps telling me syntax error on line 6 which is the “if” line and pointing to the “20” though that sometimes changes.

I’ve tried different combinations of spaces and notations, I began with

“if f(4) == 20
print(“true”)”

And changed it from there but still haven’t got a true back.

Thanks guys!

Answer 1

if f(x) < 20:
print("True")

https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2277/

Answer 2

def f(x):
return x**2 + 4

x = 2

if f(x) < 20:
print("true")