Pls, why does this code print only odd numbers in the range? And if I chnge the "if" to (x = x) it prints the full range

Question

public class Program
{
public static void main(String[] args) {
boolean x = true;
for(int i = 0;i < 11;i++){
if(x = !x)//try change = to ==
System.out.println(i);
}
}
}

I'm used to (x==x) or (x==!x)

Answer 1

This code should most definetly not print anything, as you are repeatedly checking if true == false, which it never is. Can you try to write this code in sololearn's development environment and send it to me? Ill be of better help seeing your code in there instead of in the description.

Answer 2

try this
boolean x = true;
System.out.println(x = !x); //assign into x negation of x and print result
System.out.println(x = !x);
System.out.println(x = !x);
System.out.println(x = !x);

Answer 3

Coder's Crux
Output:
1
3
5
7
9

Answer 4

Also, please, can I use "=" instead of "==" in checking boolean relational condition, e.g. "if(x = !x)" instead of "if(x == !x)"?
I'm kinda new though, if the question sounds dumb

Answer 5

Line after if( expression ) is execute only if result of expression is true.
x = 1; // mean: store into variable x value 1, then x is 1
x == 1 // mean question: Is 1 in x ? and answer is true or false
!x // mean: if true is in x result is false
if false is in x result is true

if(x=true)
is same as:
x = true // store into x value true
if(x) // if in x is true

if(x = !x)
is same as:
x = !x // change value to opposite
if(x) // if in x is true

here you change value of x in order
x: true //start value
x: false true false true false
i : 0 1 2 3 4
print 1 3 ...

Answer 6

zemiak Coder's Crux
Thanks to you guys, I get it now

Answer 7

zemiak
I actually thought of it that way, but it prints odd numbers in the range i.e. The output is:
1
3
5
7
9 //terminate

But the condition "if(i = !true)" works accordingly