c language code

Question

#include <stdio.h>

/* declaration */
int square (int num);

int main() {
int x, result;
result = square(x);
printf("enter your number here***");
scanf("%d",x);

printf("%d squared is %d\n", x, result);

return 0;
}

/* definition */
int square (int num) {
int y;

y = num * num;

return(y);
}
what could be the problem with this program

Answer 1

Inside main()
Write the result line after scanf method and include "&" before x inside the scanf.

How come you take value of x and assign it to result without even taking user input.

Answer 2

There is no problem.
Just run it and enter a number.

https://code.sololearn.com/ca9uGs3Sc4Xb/?ref=app

Answer 3

there is a problem when you run the program

Answer 4

Have u tried it out