problem in c code ???

Question

I am currently working on C and I have encountered a problem with one of the programs I am trying to apply to.

#include <stdio.h>
#include <stdlib.h>
int main(){
int x,y;
char opt;
char r;
do{
printf("============================== calculator ==============================\n");
printf("enter the first number : ");scanf("%d", &x);
printf("enter the second number : ");scanf("%d", &y);
do{
printf("chose operation between '+' or '-' or '*' or '/' or '^' :");
scanf("%c", &opt);
}while(opt != '+' && opt != '-' && opt != '*' && opt != '/' && opt != '^');
switch (opt) {
case '+': printf("%d + %d = %d\n", x, y, x+y);break;
case '-': printf("%d - %d = %d\n", x, y, x-y);break;
case '*': printf("%d * %d = %d\n", x, y, x*y);break;
case '/': printf("%d / %d = %d\n", x, y, x/y);break;
case '^': printf("%d ^ %d = %d\n", x, y, x^y);break;
}
do{
printf("do you would do another calculation y/n ? ");scanf("%c", &r);
}while(r != 'y' && r != 'n');
}while(r=='y');
return 0;
}

The problem is that when I run the program this code is repeated twice for the printf,
do{
printf("chose operation between '+' or '-' or '*' or '/' or '^' :");
scanf("%c", &opt);
}while(opt != '+' && opt != '-' && opt != '*' && opt != '/' && opt != '^');
he writes the message twice and then asks me to enter the process i don't know why
The same problem is repeated in
do{
printf("do you would do another calculation y/n ? ");scanf("%c", &r);
}while(r != 'y' && r != 'n');

Answer 1

thank you very much :)

Answer 2

The problem is he writes like this
chose operation between '+' or '-' or '*' or '/' or '^' :chose operation between '+' or '-' or '*' or '/' or '^' :

Answer 3

can you please write me the code ? I tried but I couldn't