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Why the output coming as one?

int x=2, y=10,z=7,a; a=x<y<z; cout<<a; //This question was asked in post on FB....

2nd Jan 2020, 5:29 PM
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2 Antworten
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First, the expression x < y is evaluated, which is obviously true. Since only similar data types can be compared, the result is implicitely casted to 1 (the typical boolean representation of 'true', although any numerical non-zero value is considered as true in C++), which is then compared to 'z' in 1 < z which is once again true. The variable 'a' is then assigned this result after another implicit conversion.
2nd Jan 2020, 5:50 PM
Shadow
Shadow - avatar
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Thanks Shadow .....I was evaluating the expression from the right n was guessing 0 as answer.... But now I feel dumb that I was evaluating it from right rather than left
2nd Jan 2020, 5:58 PM
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