Can anyone explain this code snippet in brief?

Question

#include <stdio.h>
struct Ournode{
char x, y, z;
};
int main() {
struct Ournode p = {'1', '0', 'a' + 2};
struct Ournode *q = &p;
printf("%c, %c", *((char *)q+1), *((char *)q+2));
return 0;
}

Answer 1

a struct with three members x,y,z

p is a struct Ournode type .
q is pointing to p memory address .

the values of x,y,z are in consecutive memory addresses .
when you do operations with pointers
it means you are jumping between addresses in memory.

q+0 --> 1 / q+1 --> 0 q+3 --> 'a'+2

char 'a' + 2 = 'c' /[abcdefg...z]
'a' + 3 = d and so on.

Answer 2

I can try.
You make a struct named Ournode.
Then you declare p of type Ournode with the char values 1 , 0 and c. ( c since you're adding 2 and the ascii value of 'a' plus 2 is c)
Then you declare a pointer, q, of type Ournode that points to p.
Then you use said pointer to access the values in p via derefrenece , so your output would be 0 and c.
Hope that helps!

Answer 3

check the output of this, it prints the memory addresses of x, y, z

printf("%p, %p, %p",q+0, q+1, q+2);

when you add * (dereference as Derbi E. Calderon said) and %c instead of %p it prints the values

Answer 4

Thanks bahha🐧 Derbi E. Calderon 👍