How to avoid consecutive occurrences of digit in regex??

Answer 1

It's really easy to adjust to only look for consecutive repetitions, not overall anywhere in the string.
.* means any character (between the same checked digits
replace with -? That means an optional dash or nothing.

rep4 = compile(r'.*(\d)-?\1-?\1-?\1')

You get help more easily if you can accurately specify your problem and people don't need to do much guesswork ;)

Answer 2

As in, you want digits which occur in singles and not in groups?

Answer 3

https://code.sololearn.com/cXqWk43n02P2/?ref=app

Answer 4

🌟(Pro)metheus 🇸🇬 yes , I want to make aUID for company employees
For that no digit will be consecutive occur 4 or more time

Answer 5

Do you have to use a regex?

Answer 6

rodwynnejones yes

Answer 7

rep4 = compile(r'.*(\d).*\1.*\1.*\1')

This matches any digit that is repeated at least 4 times. If there is no match then your input is valid. You can combine it with the other criterion (of format) as 2 separate regexp.

https://code.sololearn.com/cW16Sb5MW1D4/?ref=app

Answer 8

Give a few more examples of valid and in-valid inputs and explain why.
I don't think it can be done in the actual repression.. but you can carry out tests on what's returned if you group them.

Answer 9

Tibor Santa your program work but it gives error for input as " 5252248277877418"

Answer 10

I don't see any errors, it returns Invalid.
Anyway, feel free to adjust the code according to your needs, I've only highlighted a possible solution. ;)

Answer 11

77-77 is not valid and 77877 is valid

Answer 12

https://code.sololearn.com/c5zxiBUHM3Kv/?ref=app
Tibor Santa your expression is really best thanks I post the code for other which don't know how avoid repetition