YouTube Link Finder task

Question

import re

pattern = r"https://(www.)?[\w.]+/(watch\?v=)?([\w\d_]+)"

url = input()

match = re.match (pattern , url)
if match:
print (match.group(3))

My code isn't passing the fourth test case. What have I lost in my pattern?

Answer 1

I might have taken a shortcut 😬

inp = input()
print(inp[-11:])

Answer 2

Instead of this, I would suggest you try this idea.
We know youtube video id is starting after the v= and we also know that length of the id is 11 characters. just find the v in the link and after the v= collect 11 characters which will be the id of the YouTube video.

Answer 3

Thanks to YouTube video ID being 11 characters, my code was very simple, passed all the tests:

print(input()[-11:])

Answer 4

This was my answer:

https://code.sololearn.com/cK8wjT3bSESH/?ref=app

It’s pretty straightforward.

Answer 5

Easiest solution:

url = input()

if "=" in url:
res = url.split("=")
else:
res =url.split("/")

print(res[-1])

Answer 6

url = input()

if "watch" in url:
print(url.replace("https://www.youtube.com/watch?v=" , ""))

else:
print(url.replace("https://youtu.be/" , ""))

Answer 7

Solution by Manohar (optimized)

import java.util.*;

class Manoher
{
public static void main(String arg[])
{
Scanner sc=new Scanner(System.in);
String accept=sc.nextLine(); //String accepted
System.out.println(accept.substring(accept.length() -11));
}
}

Answer 8

not optimized code
import java.util.*;
class YoutubeLinkFetcher
{
public static void main(String arg[])
{
int no=0;
String rev="";
Scanner sc=new Scanner(System.in);
String str=sc.nextLine(); // string accepted here

for(int i=str.length();i>0;--i) //

{

rev= rev+(str.charAt(i-1)); // String has been reversed

no++;
if(no==11)
{
//System.out.println(rev);
StringBuilder xx=new StringBuilder(rev);
System.out.println(xx.reverse());

}

}

}
}

Answer 9

import re

pattern = r"https://(www.)?[\w.]+/(watch\?v=)?([\w\d_]+)"

url = input()
match = re.match (pattern , url)
if match:
print (match.group(3))
#print(match.group[-11:])
#print(input()[-11:])

Answer 10

import re

pattern = r"https://(www.)?[\w.]+/(watch\?v=)?([\w\d_]+)"

url = input()
match = re.match (pattern , url)
if match:
print (match.group(3))
#print(match.group[-11:])
#print(input()[-11:])

Answer 11

This is my solutions

url = str(input())
s = url.replace("/","").replace(":"," ").replace("="," ").replace("."," ")
ID = s.split()

if len(ID) >3:
print(ID[4])
else:
print(ID[2][2::])

Answer 12

file = open("/usercode/files/books.txt", "r")

#your code goes here
readfile=file.readlines()
for i in readfile:
sv=i.split('\n')
sv1= sv[0]
sv2=sv[0][0]
sv3=str(len(sv1))
print(sv2+sv3)

file.close()

Answer 13

#The Simplest answer 😁

link =input('')
if '=' in link :
lf1 = link.split('=')
d = lf1[-1]
print(d)
else:
lf2= link.split('/')
m = lf2[-1]
print(m)