Why this code prints “llo” as an output?

Question

I came across this example in a challenge but I dont really understand how it adds value to a string pointer.
Please help me to explain this. Thank you very much.

Char* pString=“Hello”;
pString+=2;
Printf(pString); /*llo*/

Answer 1

char* pString = “Hello”;

character pointer pString points to the first character in the string literal "Hello", 'H'.

pString += 2;

character pointer pString incremented by 2, now points to *(pString + 2), which is two characters after 'H'. The pointer now points to the first 'l' of "Hello".

printf(pString);

prints the c-style string begining from where the pointer is pointing to, to the end of the string denoted by the null character, '\0'.

Answer 2

pString is a pointer that points to the first letter of a string "Hello" that lies in memory somewhere.

Pointers can be changed to point somewhere else.

printf with "%s" takes such a char pointer and reads until it finds a 0 ('\0') in that array.

If you increase that pointer by 2 and give it to printf like this, it basically means:

'Read that string from position 2, till you get to the end marker.'

Answer 3

HonFu Hatsy Rei thank you very much, those explaintions are really helpful !