Find the element that appears once in a array

Question

Can you please help me to sole above problem in python3

Answer 1

well...atleast you've had a go, this is how I would do it:-

mylist = [1, 2, 3, 4, 5, 6, 7, 1, 2, 3, 4, 5, 6]
print(*[x for x in mylist if mylist.count(x) == 1], sep=', ')

Answer 2

What did u already try?
I see no code

Answer 3

Hurry up yourself. We also help doing homework if your part is big enough.

Answer 4

Use list comprehension and lists' "count" method.

Answer 5

rodwynnejones ....pleaaaaase discipline

Answer 6

I didn't

Answer 7

def bubblesort(arr):
n=len(arr)
for i in range(n):
if arr[0] != arr[1] and arr[0] != arr[2]and arr[0] != arr[3]and arr[0] != arr[4]and arr[0] != arr[5]and arr[0] != arr[6]and arr[0] != arr[7]and arr[0] != arr[8]and arr[0] != arr[9]and arr[0] != arr[10]and arr[0] != arr[11]and arr[0] != arr[12]and arr[0] != arr[13]and arr[0] != arr[14]and arr[0] != arr[15]and arr[0] != arr[16]and arr[0] != arr[13]and arr[0] != arr[18]and arr[0] != arr[19]:
print(arr[0])

arr = [-20, 20, -10, 20, 0, 4, 8, -20, 10, -10, 8, 6, 15, 9, 18, 35, 40, -30, -90, 99]
bubblesort(arr)

here i try one comparison of arr[0] .how can i compare every element of array with other element using for loop

i.e.
Find the elements from an array A, that appears only once.

E.g.

N = 20

A = {-20, 20, -10, 20, 0, 4, 8, -20, 10, -10, 8, 6, 15, 9, 18, 35, 40, -30, -90, 99}

Array elements which appeared only once are (order of element should not change).

= { 0, 4, 10, 6, 15, 9, 18, 35, 40, -30, -90, 99 }

Answer 8

thanks buddy