Problem with the or statement

Question

I wrote this code:

num=7
if num == 5 or 9 or 11:
print(num)
else:
print(invalid)

I got the output: 7

How is this possible when num is neither 5, 9 nor 11. The or statement is true if one of the conditions is True, which is not the case in this example.

Can someone explain this to me please.

Answer 1

This can be simplified to:
if num in (5, 9, 11)

Answer 2

thanx for ya help friends!!
turns out i just had to repeat "num" before each value.

if num == 5 or num == 9 or num == 11:

than i got the right output. i tried with more examples and it works.

Answer 3

Вазген Арутюнян This doesn't work.

Answer 4

num == 5 evaluates to a False.....then...
False or 9 evaluates to True because any number other than 0 (zero) evals to True..
then it stops there...short circuit evaluation..so the result of the whole expression is True...and num (7) is printed.
This is what your looking to do:-
if num == 5 or num == 9 or num == 11

Answer 5

Ok, I'm sorry

Answer 6

Seb TheS
thanx, it makes it a lot easier when there are many elements in the statement