+ 3
Python - Roadrunner - test case 3(hidden) fails - what am i missing?
dist_apart = 50 dist_to_safety = int(input()) rr_speed = int(input()) k_speed = int(input()) catch_rate = k_speed - rr_speed catch_time = dist_apart/catch_rate rr_safe_time = dist_to_safety/rr_speed if rr_safe_time > catch_time: print("Yum") elif rr_safe_time < catch_time: print("Meep Meep")
14 Antworten
+ 10
Your catch time is wrong. It is as if you considered that the road runner is not moving. The distance is changing with time, you forgot the add that as well.
Here is a fix:
Instead of trying to figure out catch_time, consider it as a race. If the coyote arrives first, he wins. Else, the road runner wins.
Which means, catch_time will now represent the time needed for the coyote to go to safe zone. Thus this formula:
catch_time = (dist_apart+dist_to_safety) / k_speed
Also, catch_rate will be useless if you look at the situation like I did, so you can remoce it.
+ 5
Adam technically, the road runner will be safe.
If they voth arrive to safe zone same time, then the road runner will already be safe.
But what matters is that you deliberately left it out, so no problem 👌
+ 4
Thanks Aymane. The code below now passes all test cases.
dist_apart = 50
dist_to_safety = int(input())
rr_speed = int(input())
k_speed = int(input())
k_finish_time = (dist_apart + dist_to_safety)/k_speed
rr_finish_time = dist_to_safety/rr_speed
if rr_finish_time > k_finish_time :
print("Yum")
elif rr_finish_time < k_finish_time :
print("Meep Meep")
+ 4
Adam even tho it is now fixed, you forgot about one test case:
rr_finish_time == k_finish_time
But nice code, and good choice of variables 😁👍
+ 4
distance_safety = int(input())
roadrunners_speed = int(input())
coyotes_speed = int(input())
if distance_safety / roadrunners_speed < (distance_safety + 50) / coyotes_speed:
print("Meep Meep")
else:
print("Yum")
+ 1
Thanks Aymane.
I deliberately left out that test case as the question doesn't specify what happens in the event of a draw.
+ 1
Had the same problem with test case 3... Made modifications as suggested and all cases worked but I don't get why using closing speed didn't work.... In the first code above closing time was calculated using closing rate, not just the coyote speed... In my head using the rate here accounts for both parties moving...
Speed 1 = 20
Speed 2 = 5
Closing rate = 15
So every second the become 15 feet closer....
I must be missing something!!
+ 1
I compare times needed to beat distances to safe place. If coyote beat this distance faster, that mean he coughts roadrunner.
+ 1
s = int(input())
r = int(input())
c = int(input())
d = 50
if (s + d) / c < s / r:
print("Yum")
else:
print("Meep Meep")
0
For those who cant do math like me, just replecate a real race🏁, it works for me
My roadrunner code
rrposis = int(input())
rrspeed = int(input())
caospeed = int(input())
caoposis = rrposis + 50
while caoposis > rrposis and rrposis>0:
rrposis -= rrspeed
caoposis -= caospeed
print(('Meep Meep','Yum')[rrposis>0])
The last print statment
Is just a fancy if statment trick, basicly im printing yum if rrposis >0
0
distancia = int(input())
roadrunner = int(input())
coyote =int(input())
coyote_t = 50/coyote
roadrunner_t = distancia/roadrunner
x= coyote_t - roadrunner_t
if x>0:
print('Meep Meep')
else:
print('Yum')
0
distance = 50
distance_safe = int(input())
road_runner_speed = int(input())
coyote_speed = int(input())
time = distance_safe / road_runner_speed
if time * coyote_speed <= distance:
print('Meep Meep')
else:
print('Yum')
0
d_safety= int(input())
r= int(input())
c= int(input())
time_c= (50+r)//c
time_r = d_safety//r
if time_r < time_c :
print("Meep Meep")
else:
print("Yum")
0
In test 3 the roadrunner's speed is greater than the coyote's speed. Thus catch_rate becomes negative and the program breaks. This fixes it:
if rr_safe_time > catch_time and catch_time > 0