How is the output accumulated?

Question

Could you please explain me this code? Why the output is not simply func(5)+func(4)=3+2?

Thank you very much!

https://code.sololearn.com/cREVZs0T5ux5/?ref=app

Answer 1

Arr remains alive after the first call and we have:
Arr = [0,2,4]=>len = 3 #first call
Arr = [0,2,4,0,2]=>len = 5 second call

So first + second = 3+5=8

Answer 2

Ok lets do job sharing:
You hack the code into SL coding section and I will tekk u.

In general a linked code has better chances for supoort.

Answer 3

The idea is still the same as I mentioned:

[0,2,4] #len = 3 =>line1
[0,2,4,0,2] #len = 5 =>line2
[0,2,4,0,2,0,2,4] #len=8# + [0,2,4,0,2,0,2,4,0,2] #len=10
=> len=8+10=18 =>line3.
And for line4 it's same.

Answer 4

Oma Falk noted with thanks! I’m sorry for that, the code is added.

Answer 5

Qasem oh i see! I changed ‘return len(arr)’ to ‘return arr’ and got your general idea. Thanks a lot.

However, if it returns len(arr), func(range(5))+func(range(4)) gives 18? But if it returns arr, there are 20 values in the array.

Answer 6

Qasem ohh okok, thanks for your patience to explain me the details!

Answer 7

Nemui great!