Code Coach Security

Question

import re
inp = input()
no_gaurd = re.match(r'T\$|\$T|\$x*T|Tx*\

Answer 1

s = input()
m, t = s.find("quot;), s.find("T")
x = s[t:m] if m > t else s[m:t]
print("quiet" if "G" in x else "ALARM")

Answer 2

inp = input()
T, M = (inp.find('T'), inp.find('#x27;))

if 'G' in inp[T:M] or 'G' in inp[M:T]: print('quiet')
else: print('ALARM')

Took a different approach thanks

Answer 3

layout=input().replace("x","")
print("ALARM" if "Tquot; in layout or "$T" in layout else "quiet")

Answer 4

Check out 👇

s=input()
a=0
for i in range(len(s)-1):
if s[i] =='#x27;or s[i]=='T':
for j in range(i+1,len(s)):
if s[j]=='G':
a=1
break
elif s[j]=='T' or s[j]=='#x27;:
a=2
break

if a==1:
print ("quiet")
break
elif a==2:
print("ALARM")
break

Answer 5

Use that, it may help u, but in CSharp
https://code.sololearn.com/c7VAUC96mU4N/?ref=app

Answer 6

str = list(input())
if "G" in str[str.index("T"):str.index("quot;)] or str[str.index("quot;):str.index("T")]:
print ("quiet")
else :
print ("ALARM")

Answer 7

def find_caps(x):
return [l for l in x if l.isupper() or l == '#x27;] #cut upper letter and $

string = input() # 'TxxxxxGxx$xxx'
check = ''.join(find_caps(string)) # join new string whis upper letter only

if check.find('$T') == -1 and check.find('T#x27;) == -1: # check this out
print('quiet')
else:
print('ALARM')

# PROFIT :)

Answer 8

thought this was cheeky

def solution(casino):
thief = False
money = False
guard = False
for x in casino:
if x == "quot;:
money = True
if thief and not guard:
return "ALARM"
guard = False
if x == "T":
thief = True
if money and not guard:
return "ALARM"
guard = False
if x == "G":
guard = True
if thief:
thief = False
return "quiet"

if __name__ == "__main__":
casino = input()
print(solution(casino))

Answer 9

x = ''.join(input().split('x'))

y = ''.join(x.split('T#x27;))
z = ''.join(y.split('$T'))

print('ALARM'if '#x27; not in z else 'quiet')

Noob style: passes all tests.
#x removes space.
#y&z remove only the thieves with money
#If money is gone an alarm
#else - it's all quiet

Answer 10

Try this ☺️☺️

#include<stdio.h>

int main()
{
char ch[100];
int i,f=1,j;
gets(ch);
for(i=0; ch[i]!='T'; i++);
for(j=i; j>=0; j--)
{
if(ch[j]=='#x27;)
{
f=0;
break;
}
if(ch[j]=='G')
{
f=1;
break;
}
}
if(f==1) {
for(j=i; ch[j]!=0; j++)
{
if(ch[j]=='#x27;)
{ f=0;
break;
}
if(ch[j]=='G')
{
f=1;
break;
}
}
}
if(f==1)
printf("quite");
else
printf("ALARM");
return 0;
}

Answer 11

Ruby solution
word = gets.chomp.to_s
word_new = word.gsub("x","")
if((word_new.include? "Tquot;) ||( word_new.include? "$T"))
puts 'ALARM'
else
puts 'quiet'
end

Answer 12

import re
def security(code):
if re.findall(r"(Tx*\$|\$x*T)", code):
return "ALARM"
else:
return "quiet"
print(security(input()))

Answer 13

s=input().replace("x","")

m,t = s.index('#x27;), s.index('T')
print("ALARM" if abs(m-t) ==1 else "quiet" )

Answer 14

aaa = input()
b = ''

for i in aaa:
if i != 'x':
b = b + i

if b.count('$T')<1 and b.count('T#x27;)<1:
print('quiet')
else:
print('ALARM')

Answer 15

try re.findall