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Code for different file type in a directory
How to write a code which will read a directory having both csv and psv file and do split separately
6 Antworten
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import os
dir = os.listdir()
csv = [ ]
psv = [ ]
for f in dir:
ext = os.path.splitext(f)[1].lower()
if ext == 'csv':
csv.append(f)
elif ext == 'psv':
psv.append(f)
print(csv)
print(psv)
+ 2
You may want to use os.listdir () to get a full list of files and use 'if' to see if a file is csv or psv.
+ 2
You have already two lists of filenames, which can be used / formated as you want ^^
I raw print the two arrays just to log purpose ;)
Maybe you want not split the lists, but join it in a string? 'Split' is for cuting a string as items of a list, contrarly:
str1 = '\n'.join(csv)
str2 = '|'.join(psv)
print(str1)
print(str2)
str1 = str1.split('\n')
str2 = str2.split('|')
print(str1)
print(str2)
+ 1
Yes, you must have to loop inside the files lists, opening each, reading content and split it according to the delimiter used in your csv files to get theur content in a list...
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@visph
I think i need to write split by pipe or comma separately or the above will work?
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I have to do different operations on each field of a csv file and different for psv. More of all i was looking for a config kind of function which will take the file and split them according to their delimiters. And saved in a different DF