[Solved by jayakrishna]Code coach paint cost problem in C

Question

What's wrong with my code?
It can't pass case3 and case4.

#include <stdio.h>

int main() {
int a;
scanf("%d",&a);
a*=5;
a+=40;
int b;
if(a%10==0){
b=a/10;
printf("%d",a+b);
}
else if(a%10!=0){
float c;
c=a/10;
printf("%.2f",a+c);
}

return 0;
}

Answer 1

cout<<(int)ceil(c);

for c,
int c=ceil(a+b);

Answer 2

Try by taking 'a' as double or float.
Output should rounded up, converted to int value only.

I guess the problem is in else part only.. should be %d not %f...

Answer 3

Input is number of colours, it's not something like half blue or half yellow exist right?but output did, output is price+price÷10.
I still don't get it...
pls help..

Answer 4

No. I mean if it is int, then a/10 always return int values only....
So you need, a double value to get fraction part also..
Either take 'a' as double or do like a/10.0....

Answer 5

I edit code like this it still failed in case 3 and 4.

#include <stdio.h>

int main() {
float a;
scanf("%f",&a);
a*=5;
a+=40;
float b;
b=a/10;
int c=a+b;
printf("%d",c);
return 0;
}

Answer 6

a+b is should be rounded up, so use ceil function to result of a+b, and store in c...

Answer 7

Thanks！！！
The ceil function was working successfully！

#include <stdio.h>

int main() {
float a;
scanf("%f",&a);
a*=5;
a+=40;
float b;
b=a/10;
float c=a+b;
printf("%.0f",ceil(c));
return 0;
}

Answer 8

But my cpp code failed in case 3 and 5...

#include <iostream>
#include <cmath>
using namespace std;

int main() {
float a;
cin>>a;
a*=5;
a+=40;
float b;
b=a/10;
float c=a+b,x;
x=ceil(c);
cout<<x;

return 0;
}

Answer 9

It's work！
Thanks you very much！

Answer 10

高于鈞 Wel come..