Groups with RE

Question

import re

testo="aaabbbabababaabbaabbaabbaaaabbbb"
pattern=r"(a|b)+"
print(re.findall(pattern,testo))

I don't understand why this code gives me a different result from the case where I set pattern="[ab]+".
Thanks for your time :)

Answer 1

Thats the behaviour of greedy quantifier with capturing group. It'll only take the last match from group.
So the string aaabbbabababaabbaabbaabbaaaabbbb will only take the last b.
You can however enclose it again in another group ((a|b)+). But using character class [ab]+ is much better here