What the wrong in this c++ help me

Question

https://code.sololearn.com/cisUhphfxghC/?ref=app

Answer 1

Try this
#include <iostream>
using namespace std;

int main() {
int x;
int y;
cout <<"enter x\n";
cin >>x;
cout <<"enter y\n";
cin >>y;
int sum =x+y ;
int div =x/y ;
int mu =x*y ;
cout << sum<<"\n"<<div<<"\n"<<mu<<"\n";
return 0;
}

Answer 2

at the end it should be
cout << sum << "\n" << div << "\n" << mu << "\n";
You need to seperate the strings from variables with the << operator.

I would suggest you not use "\n" but do this instead:

cout<<sum<<endl;
cout<<div<<endl;
cout<<mu<<endl;

Generaly it is better to use \n at the end of the strings but try avoiding it because endl looks more clear to the eye. That's my personal opinion

Answer 3

Yakout Yasser Yakout Aprahim Allam just remove those \n From line 15.
'\n' is used for a line break within the string.
No need of '\n' in line 15.

Answer 4

Ty

Answer 5

But if i want make all anser start from new line what should i do

Answer 6

Pls annser

Answer 7

If that's what you mean:

cout<<"enter x:"<<endl;
cin>>x;

Though it would be cool if you did that too

//That's what you did
cout<<"enter x:\n"<<endl;
cin>>x;

Answer 8

~ swim ~ Yeah that's true but in a program that you have console output with cout, I wouldn't care so much about performance since printing is really slow too

Answer 9

Pls write \n in"\n" (double inverted comas )instead of \n.

Answer 10

#include <iostream>
using namespace std;

int main() {
int x, y; // Since both return same type, you can declare them in same row
cout << "enter x\n";
cin >> x;
cout << "enter y\n";
cin >> y;
int sum = x + y;
int div = x / y; //Will not really hold the real value of a division if the number is real. It's better to divide and module the rest of the division. Like that (mod = x % y;
int mu = x * y;
cout << sum << endl << div << endl << mu << endl; // \n is mostly used when you're printing a string cause quote are already open, otherwise endl do the same without having to open quote or print string.
return 0;
}

I hope I helped out, not my native language so sorry if I have made bunch of errors.
I am as well still new with C++ programming so I might be wrong.

Answer 11

Where u wrote cout in line 14 u missed double quotes in \n

Answer 12

Ty it work

#include <iostream>
using namespace std;

int main() {
int x;
int y;
cout <<"enter x\n";
cin >>x;
cout <<"enter y\n";
cin >>y;
int sum =x+y ;
int div =x/y ;
int mu =x*y ;
cout << sum<<"\n"<<div<<"\n"<<mu<<"\n";
return 0;
}

Answer 13

do it as that is executing
#include <iostream>
using namespace std;

int main() {
int x;
int y;
int sum,div,mu;
cout <<"enter x\n";
cin >>x;
cout <<"enter y\n";
cin >>y;
sum =x+y ;
div =x/y ;
mu =x*y ;
cout << sum<<endl<<div<<endl<<mu;
return 0;
}

Answer 14

the cout line

Answer 15

Use instead of \n is <<"\n"

Answer 16

\n is come in double quoted or you yse endl instead of \n

Answer 17

Yakout Yasser Yakout Aprahim Allam
Line number 7 and 9: hit space before typing \n
Line number 14 is all messed up too. Use '\n' instead of just \n and separate it with <<.
Here is the code all fixed, refer to it and learn from your mistakes. Good luck.
https://code.sololearn.com/c8SZ5WCyw862/?ref=app

Answer 18

https://code.sololearn.com/c02MU9D9v6Yl/?ref=app

Answer 19

https://drive.google.com/file/d/1Gb62I4nLsK-3usqdqO3J-9YlbCnPEHnG/view?usp=drivesdk
Sorry i need u help

Answer 20

Line 14 should be
cout << sum <<'\n'<<div<< '\n'<<mu <<'\n';