Is there another way to solve it?

Question

https://www.sololearn.com/coach/57?ref=app
======
Idiot list
======
x = str(input())
y = list(x)
answer = ""
c1 = ["q","w","e","r","t","y","u","i","o","p","a","s","d","f","g","h","j","k","l","z","x","c","v","b","n","m"," ","1","2","3","4","5","6","7","8","9","0","Q","W","E","R","T","Y","U","I","O","P","A","S","D","F","G","H","J","K","L","Z","X","C","V","B","N","M"]
for i in y:
if i in c1:
answer += i
print(answer)

Answer 1

ss = input()
newstr = ""
for i in range(0, len(ss)):
if ss[i] in "@#amp;*%":
continue
else:
newstr += ss[i]
print(newstr)

Answer 2

Using regular expression you can solve it in easy way.

https://www.tutorialspoint.com/JUMP_LINK__&&__python__&&__JUMP_LINK/python_reg_expressions.htm

Answer 3

isalnum() string method checks whether all the characters in a string are alphanumeric, that is either Latin letters or Arabic digits. So, use it instead